Transform the following sentence into Disjunctive Normal Form.(~P∨~Q) & R→S

In Disjunctive Normal Form, all terms are seperated by disjunction.

We know that A→B = ¬A ∨ B.

Therefore, R→S can be written as ¬R ∨ S.

The whole equation now becomes,

(~P∨~Q) & ¬R ∨ S

Further,

(~P & ¬R ∨ S) ∨ (~Q & ¬R ∨ S)

This is the Disjunctive Normal Form.