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Perform the following conversions to the indicated bases

Perform the following conversions to the indicated bases:

(973)10 = (?)5

(F23A)16 = (?)8

(10110.11)2 = (?)10


Let's perform the given conversions step by step.


1. Convert (973)₁₀ to Base 5


We repeatedly divide 973 by 5 and record the remainders.


973÷5=194 remainder 3

194 ÷ 5 = 38 remainder 4

38 ÷ 5 = 7 remainder 3

7 ÷ 5 = 1 remainder 2

1 ÷ 5 = 0 remainder 1


Reading the remainders from bottom to top, (973)₁₀ = (12343)₅.


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2. Convert (F23A)₁₆ to Base 8


First, convert from hexadecimal (base 16) to binary.


F=1111, 2=0010, 3=0011, A=1010


So, (F23A)₁₆ in binary:


F23A=1111 0010 0011 1010


Now, group into triplets from right to left for conversion to octal:


1 111 001 000 111 010


Converting each triplet to octal:


1=1,111=7,001=1,000=0,111=7,010=2


So, (F23A)₁₆ = (171072)₈.


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3. Convert (10110.11)₂ to Base 10


We expand the binary number using powers of 2.


Thus, (10110.11)₂ = (22.75)₁₀.


Final Answers:

  1. (973)₁₀ = (12343)₅

  2. (F23A)₁₆ = (171072)₈

  3. (10110.11)₂ = (22.75)₁₀



 
 
 

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